6[3-(4+2x)]-2x=-8+2(1-7x)

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Solution for 6[3-(4+2x)]-2x=-8+2(1-7x) equation:


Simplifying
6[3 + -1(4 + 2x)] + -2x = -8 + 2(1 + -7x)
6[3 + (4 * -1 + 2x * -1)] + -2x = -8 + 2(1 + -7x)
6[3 + (-4 + -2x)] + -2x = -8 + 2(1 + -7x)

Combine like terms: 3 + -4 = -1
6[-1 + -2x] + -2x = -8 + 2(1 + -7x)
[-1 * 6 + -2x * 6] + -2x = -8 + 2(1 + -7x)
[-6 + -12x] + -2x = -8 + 2(1 + -7x)

Combine like terms: -12x + -2x = -14x
-6 + -14x = -8 + 2(1 + -7x)
-6 + -14x = -8 + (1 * 2 + -7x * 2)
-6 + -14x = -8 + (2 + -14x)

Combine like terms: -8 + 2 = -6
-6 + -14x = -6 + -14x

Add '6' to each side of the equation.
-6 + 6 + -14x = -6 + 6 + -14x

Combine like terms: -6 + 6 = 0
0 + -14x = -6 + 6 + -14x
-14x = -6 + 6 + -14x

Combine like terms: -6 + 6 = 0
-14x = 0 + -14x
-14x = -14x

Add '14x' to each side of the equation.
-14x + 14x = -14x + 14x

Combine like terms: -14x + 14x = 0
0 = -14x + 14x

Combine like terms: -14x + 14x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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